22x^2+37x+6=0

Solution for 22x^2+37x+6=0 equation:

22x^2+37x+6=0

a = 22; b = 37; c = +6;
Δ = b2-4ac
Δ = 372-4·22·6
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-29}{2*22}=\frac{-66}{44}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+29}{2*22}=\frac{-8}{44}
=-2/11
$